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Forum Contest - March Calculus

LagerthaLagertha Posts: 957
edited 03.03.2020 in Real-Life & Off-Topic
Dear Lords and Ladies, 

As commanders of countless battles, your knowledge and skill are based on a multitude of experiences. 
Among other things, this includes having a keen eye on your army, regarding the number of troops under your banners. 

During one of your daily visits, you want to discuss the number of recently recruited troops with your vasals. 
But none of them seem to meet your gaze, as they look down to the floor, ashamed of something which you cannot quite grasp yet. 
The vassal to your right slowly pushes the reason for this prevalent embarrassment towards you.

Self-assured, you're having a look at the pamphlet and are met with the following calculation: 



Well commander, - it is your turn as a paragon of calculus to solve this riddle of numbers for your vasals. Make sure to announce your answer in this discussion in order to share it with everyone. 

Competition Rules

Every participant is allowed to post one answer only. Two answers or more will automatically disqualify the respective participant from this competition. 

We will pick a maximum of 10 participants with the correct answer as winners of this competition. The picked winners will thereby obtain 10.000 rubies each. And to top that: One of them will have the chance to obtain one of our new Throne of the Community decoration with an incredible public order of 500. 

Picking the winners will be ultimately done by the jury of forum board members and will as such be valid and final. 

Good luck to all of the participants! 
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Comments

  • CM_WylkaCM_Wylka Community Manager Posts: 694
    Greetings everyone! 

    The decoration being discussed previously is the newest- and strongest version of our Throne of the Community decoration and this one has an incredible amount of 500 public orders! 

    The decoration itself will look as follows: 

  • Lord Drab (PL1)Lord Drab (PL1) PL1 Posts: 182
    54
    Lord Drab @ GS2 1
  • MrChaos (SKN1)MrChaos (SKN1) SKN1 Posts: 189
    edited 04.03.2020
    54
    Post edited by MrChaos (SKN1) on
  • scipiosmith (US2)scipiosmith (US2) US2 Posts: 100
    9
  • Evans3531 (GB1)Evans3531 (GB1) GB1 Posts: 96
    edited 03.03.2020

    54

    Post edited by Evans3531 (GB1) on
    Evans3531 @ GG 1
  • WillyWiz (NL1)WillyWiz (NL1) NL1 Posts: 1,139

    54

  • Maeve (US2)Maeve (US2) US2 Posts: 4

    54

  • Evans3531 (GB1)Evans3531 (GB1) GB1 Posts: 96

    54

    Evans3531 @ GG 1
  • Evans3531 (GB1)Evans3531 (GB1) GB1 Posts: 96

    When will the winners be announced?

    Evans3531 @ GG 1
  • 54

  • 54
    lufc crazy @ GG 1
  • 54
  • Chellee (US2)Chellee (US2) US2 Posts: 2

    54

  • 24

  • raleed (FR1)raleed (FR1) FR1 Posts: 426
    9
    raleed @ GG 1
  • 54

  • Riraroutch (FR1)Riraroutch (FR1) FR1 Posts: 7
    edited 05.03.2020
    9
  • NicAM (GB1)NicAM (GB1) GB1 Posts: 25

    54

  • 9
  • Tacticus (INT4)Tacticus (INT4) INT4 Posts: 162
    54
    Couple of things wrong here, the two soldiers are misleading. Do they mean times? Do they mean the two numbers are next to each other? Or is it implying one is a power. 
    Oh well.
  • Rotman (US1)Rotman (US1) US1 Posts: 2
    54
  • T Sauron (INT4)T Sauron (INT4) INT4 Posts: 1
    54
  • 9
  • First assume the soldier in first equation to be x. The first following soldier ( the one with the small knife) will be substituted by y and the last by z ( the one with the torch).

    Either 9 if you assume the 2 identical soldiers next to eachother in the last equation to be added up eachother which gives 10. You can derive this from the 1st equation by dividing 15 by 3 which results into 5. ( i.e. 3x = 15 => x= 5) For the 2nd and 3rd equation you need to substitute the first soldier in the 2nd equation by y = 12 - (x + z) into the 3rd equation which results into 12 - (x+z) + z+z = 10. After simplifying this equation and using the previously calculated x=5, you'll get that z = 3. So as mentioned earlier if we rewrite the last equation assuming we add up the x's we'll get 2x +z -y = 2 *5 +3 -4 =9

    If we assume the identical soldiers in the lasy equation to be multiplied by eachother will be

    x^2 + z -y = 25 + 3 -4 =24

    And last but not least if we assume the identical soldiers in the last equation to be considered as digits that create a number when putting them next to eachother we'll get

    xx +z -y = 55 + 3 -4 = 54

    N.B.: I purposefully noted the operations for multiplications so when not used you wouldn't assume it would be multiplication.

  • WillyWiz (NL1)WillyWiz (NL1) NL1 Posts: 1,139

    I think this is a fine example of having two fora (this one and Discord) is not the smartest thing to do. The same contest was also on Discord. There winners were already announced I think a week after the start of the contest.

    Here (on the dead forum) the contest still lingers on forever and no winner will be announced here. It is difficult to get used to a dead forum.

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